y=1/2(x-3)^2

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Solution for y=1/2(x-3)^2 equation:


x in (-oo:+oo)

y = (1/2)*(x-3)^2 // - (1/2)*(x-3)^2

y-((1/2)*(x-3)^2) = 0

(-1/2)*(x-3)^2+y = 0

y-1/2*(x-3)^2 = 0

y-1/2*(x-3)^2 = 0

3*x-1/2*x^2+y-9/2 = 0

3*x-1/2*x^2+y-9/2 = 0

3*x-1/2*x^2+y-9/2 = 0

DELTA = 3^2-(-1/2*4*(y-9/2))

DELTA = 2*(y-9/2)+9

2*(y-9/2)+9 = 0

2*(y-9/2)+9 = 0

2*y = 0

2*y = 0

2*y = 0 // : 2

y = 0

DELTA = 0 <=> t_3 = 0

x = -3/(-1/2*2) i y = 0

x = 3 i y = 0

( x = ((2*(y-9/2)+9)^(1/2)-3)/(-1/2*2) or x = (-(2*(y-9/2)+9)^(1/2)-3)/(-1/2*2) ) i y > 0

( x = 3-(2*(y-9/2)+9)^(1/2) or x = (2*(y-9/2)+9)^(1/2)+3 ) i y > 0

y+0 > 0

y > 0

y+0 > 0 // - 0

y > 0

x in { 3, 3-(2*(y-9/2)+9)^(1/2), (2*(y-9/2)+9)^(1/2)+3 }

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